Comments on: Determining the difficulty of Arithmetic Operations

By: James

James — Fri, 19 Sep 2008 05:32:25 +0000

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By: prashanthellina

prashanthellina — Mon, 04 Aug 2008 15:56:26 +0000

Karthik, the odd-even combinations I came up with for assessing difficulty may be subjective. We memorize a lot of simple operations thereby making them lookups. I have not found a convincing way of capturing this aspect.

By: Karthik Bala

Karthik Bala — Fri, 01 Aug 2008 07:34:18 +0000

brilliant work prashanth, algorithms are simply superb, didnt got time to look into the details
addition_difficulties = {
‘digit_zero’ : 1, # any digit added to zero
‘even_even’ : 2, # sum of even digits
‘odd_odd’ : 2, # sum of odd digits
‘even_odd’ : 3, # sum of even and odd digits
‘carry’ : 2 # difficulty of carry (for remembering and then adding)
}
i don’t c a difference for a no. is either odd or even, i c complexity increases as the no.s moves on the scale of 0-9. adding 7+6(odd_even) is equally difficult as adding 7+5(odd_odd) and even equally difficult as 8+6(even_even) i feel the patterns that we remember like 6+4, 5+5, 7+3 (i think we love 10) make adding some no.s easy, another example i remember is 8+4. I remember as a child i don’t know these patterns, so not taking any patterns into consideration for me its only the bigger the no.s more the complexity.
i fear if there is any technique thts helping all the humans make the odd_odd or even_even additions easier which am missing all these years

By: prashanthellina

prashanthellina — Wed, 30 Jul 2008 13:34:25 +0000

Hehe! I could not have used Vedic math here because I am trying to reproduce the mental process that most people go through when computing these kind of problems.

By: bg

bg — Wed, 30 Jul 2008 11:00:51 +0000

omg! i think u cud have figured the addition/multiplication of ‘large’ ‘difficult’ numbers manually by the time u wrote the code! but good one indeed. I have a feeling the code will be a lot simpler if you used the tricks of Vedic Math